x^2-3x+2.5=(x-3)+0.5(x-18)

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Solution for x^2-3x+2.5=(x-3)+0.5(x-18) equation: 



x^2-3x+2.5=(x-3)+0.5(x-18)

We move all terms to the left:

x^2-3x+2.5-((x-3)+0.5(x-18))=0



We calculate terms in parentheses: -((x-3)+0.5(x-18)), so:

(x-3)+0.5(x-18)

We multiply parentheses

(x-3)+0.5x-9

We get rid of parentheses

x+0.5x-3-9

We add all the numbers together, and all the variables

1.5x-12

Back to the equation:

-(1.5x-12)



We get rid of parentheses

x^2-3x-1.5x+12+2.5=0

We add all the numbers together, and all the variables

x^2-4.5x+14.5=0

a = 1; b = -4.5; c = +14.5;
Δ = b2-4ac
Δ = -4.52-4·1·14.5
Δ = -37.75
Delta is less than zero, so there is no solution for the equation

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